(7/8)+(9/8x)=(2/x^2)

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Solution for (7/8)+(9/8x)=(2/x^2) equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(9/8)*x+7/8 = 2/(x^2) // - 2/(x^2)

(9/8)*x-(2/(x^2))+7/8 = 0

(9/8)*x-2*x^-2+7/8 = 0

9/8*x^1-2*x^-2+7/8*x^0 = 0

(9/8*x^3+7/8*x^2-2*x^0)/(x^2) = 0 // * x^4

x^2*(9/8*x^3+7/8*x^2-2*x^0) = 0

x^2

(9/8)*x^3+(7/8)*x^2-2 = 0

(9/8)*x^3+(7/8)*x^2-2 = 0 // * 0

{ 1, -1, 2, -2, 4, -4, 8, -8, 16, -16 }

1

x = 1

9*x^3+7*x^2-16 = 0

1

x-1

9*x^2+16*x+16

9*x^3+7*x^2-16

x-1

9*x^2-9*x^3

16*x^2-16

16*x-16*x^2

16*x-16

16-16*x

0

9*x^2+16*x+16 = 0

DELTA = 16^2-(4*9*16)

DELTA = -320

DELTA < 0

x in { 1}

x = 1

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